Very easy solution of my old conjecture
Like a complete idiot, this took me a few years to disprove my conjecture, despite the proof is quite trivial.
Here is the complete solution:
Example ![[S]\ne\{\bigsqcup^{\mathfrak{A}}X \mid X\in\mathscr{P} S\}](https://s0.wp.com/latex.php?latex=%5BS%5D%5Cne%5C%7B%5Cbigsqcup%5E%7B%5Cmathfrak%7BA%7D%7DX+%5Cmid+X%5Cin%5Cmathscr%7BP%7D+S%5C%7D&bg=ffffff&fg=444444&s=0 "[S]\ne\{\bigsqcup^{\mathfrak{A}}X \mid X\in\mathscr{P} S\}")
![[S]](https://s0.wp.com/latex.php?latex=%5BS%5D&bg=ffffff&fg=444444&s=0 "[S]")
Proof Consider any infinite set 
But
Buy books
Like a complete idiot, this took me a few years to disprove my conjecture, despite the proof is quite trivial.
Here is the complete solution:
Example
Proof Consider any infinite set
But
Leave a Reply